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(1/125)^(24-x^2)=5^15x
We move all terms to the left:
(1/125)^(24-x^2)-(5^15x)=0
Domain of the equation: 125)^(24-x^2)!=0We add all the numbers together, and all the variables
x∈R
(+1/125)^(24-x^2)-5^15x=0
We multiply all the terms by the denominator
(+1-5^15x*125)^(24-x^2)=0
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